Geometry of Solar Eclipses

The geometry associated with solar eclipses is illustrated in the following figure, which is not drawn to scale. The various types of solar eclipses that are illustrated will be discussed further later in this module.

The Umbra and Penumbra
The shadow cast by the Moon can be divided into the completely shadowed umbra and the partially shadowed penumbra. A total solar eclipse requires the umbra of the Moon's shadow to touch the surface of the Earth. Because of the relative sizes of the Moon and Sun and their relative distances from Earth, the path of totality is usually only a few hundred kilometers across.

Path of Totality

The preceding figure illustrates the path of totality (the region on the Earth's surface where the eclipse is total) produced by the umbra of the Moon's shadow. We do not show the penumbra, which will produce a partial eclipse in a much larger region on either side of the path of totality. Here is an animation illustrating a total solar eclipse.

Technically Speaking: Angular Diameter and Linear Diameter

When an angle is small, the equations of trigonometry simplify and we obtain small angle formulas. A very important small angle formula in astronomy relates the angular diameter of an object on the celestial sphere to its distance from us and its linear diameter. It can be expressed as (see the adjacent figure)

a = 206,265 (d / r )

where a is the angular diameter in seconds of arc, d is the linear diameter, and r is the distance to the object. (The equation in this form gives the angle in arc seconds because the factor 206,235 is the conversion from radians to arc seconds.) For example, the Sun has a linear diameter of about 1.4 million km and is on average about 150,000,000 kilometers from us. Its angular diameter is thus

a = 206,265 x (1,400,000 km / 150,000,000 km) = 1925" of arc

which is a little over 1/2 degree. Alternatively, the above equation can be solved for any one of the three variables given the value of the other two. For example, the Moon also has an angular diameter of about 1/2 degree but is at a distance of only 384,000 km. We can solve the above equation for d to conclude that the Moon must be about 3500 km in diameter. That we can observe such spectacular total solar eclipses from Earth thus results from a remarkable coincidence: even though the Sun and Moon are at very different distances and have very different linear diameters, they subtend almost exactly the same angular diameter on the celestial sphere.

This Java calculator can be used to solve the above equation automatically.